Question

me ajudem a resolver

Answer 1

$\sqrt{3^3} \times 3^{ \frac{1}{2}}= \\ \\ \sqrt{3^3} \times \sqrt{3} = \\ \\ \sqrt{3^3.3} = \sqrt{3^{3+1}} = \sqrt{3^4} =3^2=9$ 

ou pode assim

$3^{ \frac{3}{2}} \times3^{ \frac{1}{2} }=3^{ \frac{3}{2} + \frac{1}{2}}=3^{ \frac{4}{2}} =3^2=9$ 

ou assim

$\sqrt{27} \times \sqrt{3} = \sqrt{81} =9$