Question

5 x² - 3 x - 2 Formula de Bhaskara

Answer 1

Δ= b² - 4 .a .c 
Δ= (-3)² - 4 . 5 . (-2)
Δ= 9 + 40
Δ= 49

$x = \frac{-b+- \sqrt{delta} }{2.a} =>x= \frac{-(-3)+- \sqrt{49} }{2.5} => x= \frac{3+-7}{10}$

$x'= \frac{3+7}{10}= \frac{10}{10}=1 \\ \\ x''= \frac{3-7}{10} = \frac{-4}{10}$

S{1,-4/10}