Question

resolver x2-10x+25=0

Answer 1

x² - 10x + 25 = 0

Delta = b² - 4ac
Delta = (-10)² - 4(1)(25)
Delta = 100 - 100
Delta = zero

X = (-b +- raiz delta) / 2a
X = (10 +- 0) / 2
x' = (10 + 0) / 2 = 10/2 = 5
x" = (10 - 0) / 2 = 10/2 = 5

BONS ESTUDOS

Answer 2

x2-10x+25=0

Δ=b^2-4ac

Δ=(-10)^2 -4.1.25

Δ=100-100

Δ=0

x=-b+-√Δ   /2a

x=10+-0    /2

x1=10+0   /2 =10/2=5

x2=10-0    /2 =10/2=5