Question

Resolva a inequação:
(2x-1)^{2} < 16

Answer 1

Vamos lá:

$(2x - 1)^2 < 16 \\\ 2x - 1 = \pm 4 \\\ 2x - 1 < 4 \\\ 2x < 4 + 1 \\\ 2x < 5 \\\ x < \frac{5}{2} \\\\ 2x - 1 > - 4 \\\ 2x > - 4 + 1 \\\ 2x > - 3 \\\ x > - \frac{3}{2}$

S = {x E R/ -3/2 < x < 5/2}

Espero ter ajudado.