Question

Utilizando o Teorema de Pitagoras, encontre o x

Answer 1

$(3x)^2+(4x)^2=20^2\\ \\ 9x^2+16x^2=400\\ \\ 25x^2=400\\ \\ x^2=\frac{400}{25}\\ \\ x^2=16\\ \\ x=\sqrt{16}\\ \\ x=4$

Answer 2

Teorema de Pitagoras

${c}^{2} + {c}^{2} = {h}^{2}$
$4 {x}^{2} + 3x {}^{2} = {20}^{2} \\ 7x {}^{2} = 400 \\ {x}^{2} = \frac{400}{7}$
$x = \frac{20 \sqrt{7} }{7}$
$x_{2} = - \frac{ 20\sqrt{7} }{7}$