Question

como resolver equação
$y {2} + 8y - 7 = 0$

Answer 1

$y^{2}+8y-7=0$
Δ=b²-4ac
Δ=8²-4*1*(-7)
Δ=64+28
Δ=92

x1=(-b-√Δ)/2a=(-8-√92)/2=(-8-2√23)/2=-4-√23

x2=(-b+√Δ)/2a=(-8+√92)/2=(-8+2√23)/2=-4+√23