Question

Como resolver a equacao x.(X+40)=1200

Answer 1

x^2 + 40x - 1200 = 0
Δ = 40^2 - 4.1.-1200
Δ = 1600 + 4800
Δ = 6400

x = - 40 +- raiz6400 /2.1
x = -40 +- 80 /2
x' = -40 + 80 /2
x' = 20
x"= -40 - 80 /2
x"= -120 /2
x" -60    
S=(20,-60)