Question

se log 2 = 0, 30, log 3 = 0, 47 e log 5 = 0, 69, calcule log 32/15

Answer 1

32=2^5
15=3.5

log32/15=
log32-log15=
log2^5-log3.5=
5log2-(log3+log5)=
5.0,3-(0,47+0,69)=
1,5-(1,16)=
1,5-1,16=
0,34