Question

sabendo que a²- b² = 34 e (a+b²)= 64,calcule o valor de 6 ab,sendo a > 0 e b > 0.

Answer 1

a²-b²=(a+b)(a-b)
(a+b)²=a²+2ab+b²

(a+b)(a-b)=34

(a+b)²=64
a+b=8

8(a-b)=34
a-b=34/8=17/4

a+b=8
a-b=17/4 +
_______
2a=8+17/4
2a=49/4
a=49/8

b=8-49/8
b=64-49/8
b=15/8

6.49/8.15/8=4410/8