Question

Se p(x)=x²-x e q(x)=3x+1, então p(x).q(x) vale:

Answer 1

Se p(x)=x²-x e q(x)=3x+1, então p(x).q(x) 

p(x).q(x)  =(x²-x) * (3x+1)

=x²*(3x+1) -x*(3x+1)

=3x³+x²-3x²-x

=3x³-2x²-x