Question

determine a raiz das seguinte equaçoes
6(4-a)-12=-5(2a+4)

3-4(x-1)=4x-3(4x-1)+3

2y-4(2y-1)=3(5y-3)-8

Answer 1

6(4 -a) -12 = -5(2a +4)
24 -6a -12 = -10a +4
12 = -4a +4
4a = -8
a = -2


3 -4(x -1) = 4x -3(4x -1) +3
3 -4x +4 = 4x -12x +3 +3
7 -4x = -8x +6
1 = -4x
-1 = 4x
x = $\frac{1}{4}$


2y -4(2y -1) = 3(5y -3) -8
2y -8y +4 = 15y -9 -8
-6y + 4 = 15y -17
21y = 21
y = 1