Question

utilizando a ideia intuitiva de limite, calcule
$lim \frac{4 {x}^{2} - 1 } {2x - 1}$
valor do limite= x-----1/2

Answer 1

Vamos lá .

$\lim_{x \to \ \frac{1}{2} } \frac{4 x^{2} -1}{2x-1} _$ = $\lim_{x \to \ \frac{1}{2} } \frac{(2x+1).(2x-1)}{2x-1} _$ 

$\lim_{x \to \ \frac{1}{2} } \frac{4 x^{2} -1}{2x-1} _$ = $\lim_{x \to \ \frac{1}{2} } 2x+1_$

$\lim_{n \to \ \frac{1}{2} } \frac{4 x^{2} -1}{2x-1} _$ = $2. \frac{1}{2} + 1 = 2$