Question

Alguém me ajuuuuuda??
$(3x + 4) {?}^{2}$
AJUUUUUUUUUUDAAAAAAAAAAA

Answer 1

aplique a propriedade distributiva
(3x+4)*(3x+4)=3x*3x+3x*4+3x*4+4*4
9x^{2}+12x+12x+16
9x^{2}+24x+16

agora siga com a fórmula de bhaskara 
Δ=b^{2}-4ac
Δ=24^{2}-4*9*16
Δ=576-576
Δ=0

x=-b+-\sqrt{Δ} /2
x=-24+-0/2
x'=$\frac{-24+0}{2}$
x'=-12
x"=$\frac{-24-0}{2}$
x"=-12