Question

resolva:

a) x²₊7x+12=0
b) x²₋2x₋35=0
c) x²₊11x₊24=0

Answer 1

A) x²+7x+12=0 
Δ= b²-4(a) (c)
Δ=7²-4(1)(12)
Δ=49-48
Δ=1

x'= -b+√1/ 2(a)               x''= -b - √1/2(a)
x'= -7+1/2 (1)                 x''= -7- 1/2 (1)
x'= -6/2= -3                     x''= -8/2= -4

B)x²-2x-35=0
Δ= (-2)²-4(1) (-35)
Δ=4+140
Δ=144

x'=2+12/2(1)          x''=2 -12/2(1)
x'=14/2=7               x''= -10/2=-5

C)x²+11x+24=0
Δ= (-11)²- 4(1) (24)
Δ= 121-96= 25

x'= -11+√25/2(1)
x'= -6/2= -3
 
x''= -11- 5/2(1)
x''= -16/2= -8

Marque a '' Melhor resposta''!! ^^