Question

Alguem que possa fazer esta? agradeço muito

Answer 1

$\left[\begin{array}{ccc} \frac{1}{16}& a^{2}\\-27& 3^{x}= \frac{1}{81} \end{array}\right]$

$\left[\begin{array}{ccc} \frac{1}{16}& a^{2}\\-27&3^{-4} \end{array}\right]$

$\left[\begin{array}{ccc} \frac{1}{16}& a^{2}\\-27&3^{-4} \end{array}\right] = \left[\begin{array}{ccc} 2^{b}&9 \\ a^{3} & c\end{array}\right]$

$\frac{1}{16} = 2^{b}$
$\frac{1}{ 2^{4} }= 2^{b}$
$2^{b}= 2^{-4}$


$a^{2} =9$
$a^{2} =3^{2}$

$-27=a^{3}$
$- 3^{3} = a^{3}$

$3^{-4} =c$

$\left[\begin{array}{ccc} \frac{1}{16}& 3^{2}\\-27&3^{-4} \end{array}\right] = \left[\begin{array}{ccc} 2^{-4}&9 \\ 3^{3} & 3^{-4}\end{array}\right]$

e não tenho informação ta matriz c.