Question

dada a função f(x)=x2+1/5,calcule P(2/5)

Answer 1

$f(x)=x^2+\frac{1}{5}\\ \\ \boxed{f\left(\frac{2}{5}\right)=\left(\frac{2}{5}\right)^2+\frac{1}{5}=\frac{4}{25}+\frac{1}{5}=\frac{4+5}{25}=\frac{9}{25}}$

Answer 2

F(x) = x² + 1/5

F(2/5)

Substituir x

$\mathtt{F(\dfrac{2}{5}) = (\dfrac{2}{5})~^2 + \dfrac{1}{5}} \\ \\ \\ \mathtt{F(\dfrac{2}{5}) = \dfrac{4}{25} + \dfrac{1}{5}~~=~~\dfrac{20 + 25}{125}~~=~~\dfrac{45}{125}~~(\div5)~~=~~\dfrac{9}{25}} \\ \\ \\ \boxed{\boxed{\mathtt{Resposta : \dfrac{9}{25}}}}$