Question

$a) \: \frac{x}{7} = - 2$
$b) \: x + \frac{1}{3 } = \frac{4}{3}$
$c) \frac{x + 3}{2} - \frac{x + 2}{3} = 12$
$d) \frac{3y + 1}{13} - \frac{2 - y}{2} = \frac{4y - 1}{5} - \frac{2y - 5}{3}$

$\frac{1}{3} x + \frac{1}{5} x$

$\frac{1}{2} x + \frac{1}{3} x$

$\frac{1}{2} x + \frac{1}{3} x + \frac{1}{4} y$
Me ajudem por favor

Answer 1

a.

x = -2*7

x = -14

b.

x = (4 -1)/3

x = 3/3 = 1

c.

3(x + 3) -2(x + 2) = 12 * 6

3x -2x +9 -4 = 72

x = 72 -5 = 67

d.

6y +2 -(26 -13y) = 12y -3 -(10y -25)

6y +13y -12y +10y = -3 +25 +26 -2

17y = 46

y = 46/17

e.

(3 + 5)/15 * x

8x/15

f.

(1/2 + 1/3)x

((3 + 2)/6)x = 6x/5

g.

6x/5 +1y/4