Question

pfv Alguém pode me ajudar a responder essa atividade quem Quem souber fala aqui me responda por favor

Answer 1

(x+y)^2=x^2+2xy+y^2

a)x=a^2 y=1

(a^2+1)^2=(a^2)^2+2(a^2)(1)+(1)^2

(a^2+1)^2=a^4+2a^2+1

b)x=y^5 y=3

(y^5+3)=(y^5)^2+2(y^5)(3)+(3)^2

(y^5+3)^2=y^10+6y^5+9

c)x=y^5 y=1

(y^5+1)^2=(y^5)^2+2(y^5)(1)+(1)^2

(y^5+1)^2=y^10+2y^5+1

d)x=4x^2 y=7

(4x^2+7)^2=(4x^2)^2+2(4x^2)(7)+(7)^2

(4x^2+7)^2=16x^4+56x^2+49

e)x=2x^3 y=3y^2

(2x^3+3y^2)^2=(2x^3)^2+2(2x^3)(3y^2)+(3y^2)^2

(2x^3+3y^2)^2=4x^6+12x^3y^2+9y^4

f)x=a^2 y=b^2

(a^2+b^2)^2=(a^2)^2+2(a^2)(b^2)+(b^2)^2

(a^2+b^2)^2=a^4+2a^2b^2+b^4

g)x=x y=2y^3

(x+2y^3)^2=(x)^2+2(x)(2y^3)+(2y^3)^2

(x+2y^3)^2=x^2+4xy^3+4y^6

h)x=mn^2 y=4

(mn^2+4)^2=(mn^2)^2+2(mn^2)(4)+(4)^2

(mn^2+4)^2=m^2n^4+8mn^2+16

Espero ter ajudado!!!!