Question

Vamos calcular
1) (2y² - 3ay + 4a² ) - (ay-5y²) =

2) (3a³-2a²b+5ab²-6b³)+(7a²b-5a³+b³-6ab² =

3) (x²-3xy+y²-x²y²) -(-x²-5x²y²-y²-3xy) =

Answer 1

1) 2y² - 3ay + 4a² - ay + 5y²
7y² - 4ay + 4a²


2) 3a³ - 2a²b + 5ab² - 6b³ + 7a²b - 5a³ + b³ - 6ab²
3ab² - 2a³ + 5a²b + 11ab² - 5b³

3) x² - 3xy + y² - x²y² + x² + 5x²y² + y² + 3xy
2x² + 4x²y² + 2y²