Question

por favor me ajuda não consigo encontra o resultado

se puder tira minha duvida agradeço

Answer 1

$a)\\ \\ 3x^{3} -4x^{3} =x^{3} (3-4)=x^{3} .(-1)=-x^{3} \\ \\ b)\\ \\ 4x^{2} +7xy+2x^{2} -2y^{2} =4x^{2} +2x^{2} +7xy-2y^{2} =\\ \\ 6x^{2} +7xy-2y^{2} \\ \\ c)\\ \\ 6a-4b-3a+2b=6a-3a-4b+2b=3a-2b$

$d)\\ \\ 13y^{2} +8y^{2} -9y^{2} =12y^{2}$

$e)\\ \\ 7y^{2} -3y^{2} +5y^{3} +7y^{3} =4y^{2} +12y^{3} \\ \\ f)\\ \\ 6x^{2} +4x^{2} -9x^{2} +11x^{2} =12x^{2} \\ \\ g)\\ \\ 9x^{3} -3x^{3} +6x^{3} -3y^{4} -5y^{4} =12x^{3} -8y^{4} \\ \\ h)\\ \\ 5x^{2} -6x^{2} +13y-7y=-x^{2} +6y$

$i)\\ \\ 5ax-3by+4by-2ax+4ax-10by=\\ \\ 5ax-2ax+4ax-3by+4by-10by=\\ \\ 7ax-9by\\ \\ j)\\ \\ 8x-(-10x)+(-3x)=8x+10x-3x=15x\\ \\ k)\\ \\ y-\frac{y}{4} +\frac{y}{2} =\frac{y}{1} -\frac{y}{2} +\frac{y}{4} =\\ \\ mmc=4\\ \\ \frac{4y-2y+y}{4} =\frac{3y}{4}$