Question

(8-x)•(8+x) quanto é?

(8+3x)•(10+3x elevado a 2) quanto é?

Answer 1

(8-x)•(8+x) quanto é?

= (8-x).(8+x)
= 64 + 8x - 8x - x^2
= 64 - x^2

(8+3x)•(10+3x elevado a 2) quanto é?

= (8+3x).(10+3x^2)
= 80 + 24x^2 + 30x + 9x^2
= 33x^2 + 30x + 80