Question

10 pontos
$-x2+6x+12=0$

forma de baskara

Answer 1

-x² + 6x + 12 = 0

a = -1
b = 6
c = 12

∆ = b² - 4ac
∆ = 6² - 4 • (-1) • 12
∆ = 36 + 48
∆ = 84

x = (-b ± √∆)/2a
x = (-6 ± √84)/(2 • -1)

x' = -6 + √84/-2
x'' = -6 - √84/-2