Question

2x^2-10x-12+0 alguém pode responder por favor :/

Answer 1

$2x^{2} -10x-12=0$

Δ = b² - 4.a.c

Δ = -10² - 4.2.(-12)

Δ = 100 + 96

Δ = 196

$x=\frac{-b+-\sqrt{delta}}{2a} \\ \\ x=\frac{10+-\sqrt{196}}{4} \\ \\ x=\frac{10+-14}{4} \\ \\ x'=\frac{10+14}{4} =\frac{24}{4} =6\\ \\ x''=\frac{10-14}{4} =-\frac{4}{4} =-1\\ \\ (x'=6;~x''=-1)$

Answer 2

2x^2-10x-12=0\

Use:

ax^2+bx+c=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-\left(-10\right)\pm\sqrt{{10}^2-4\bullet2\bullet\left(-12\right)}}{2\bullet2}

x=\frac{10\pm\sqrt{100+96}}{4}

x=\frac{10\pm\sqrt{196}}{4}

x=\frac{10\pm14}{4}

x_1=\frac{10+14}{4}\ =>\ x_1=\frac{24}{4}=6

x_2=\ \frac{10-14}{4}\Rightarrow\ x_2=\frac{4}{4}\ =1