Question

calcule: (1) 4^2 + 2^-4=? (2) 2^5 - 1^8 + 2^-1=? (3) 3^-2 ÷ 1 sobre 9 + 2^4.2^-2=?

Answer 1

(1)
= 4^2 + 2^-4
=16 + 1/16
= (16.16 + 1)/16
= (256+1)/16
= 257/16

(2)
= 2^5 - 1^8 + 2^-1
= 32 - 1 + 1/2
= 31 + 1/2
= (2.31 + 1)/2
= (62 + 1)/2
= 63/2

(3)
= 3^-2 ÷ 1 sobre 9 + 2^4.2^-2
= 3^(-2) : 1/9 + 2^[4 +(-2)]
= 3^(-2) : 3^(-2) + 2^2
= 1 + 4
= 5

Answer 2

1) 4² + 2⁻⁴ =

16 + 1/16 =

MMC = 16

(256 + 1)/16 =

257/16

2) 2⁵ - 1⁸ + 2⁻¹ =

32 - 1 + 1/2 =

MMC = 2

( 64 - 2 + 1)/2 =

63/2

3) (3⁻² : 1)/9 + 2⁴ . 2⁻² =

(1/9 :1)/(9 + 16 . 1/4 )=

( 1/9 : 1)/ (9 + 4) =

1/9 : 13 =

1/9 . 1/13 =

1/117