Question

calcular (3/0) + (4/1) +(5/2) +.......+(9/6) pfv me ajudem

Answer 1

$\frac{3}{0} + \frac{4}{1} + \frac{5}{2} + \frac{9}{6} = \frac{21}{9} \frac{( \div 3)}{( \div 3)} \\ \frac{7}{3}$