Question

X elevado a 2 + 5x-6=0?

Answer 1

x² + 5x - 6 = 0

Δ = 5² - 4 . 1 . (-6)

Δ = 25 + 24

Δ = 49

x = (-5+-√49)/2

x = (-5+-7)/2

x' = (-5-7)/2 => -12/2 => -6

x" = (-5+7)/2 => 2/2 => 1

S = {-6, 1}

Answer 2

Vamos lá

X² + 5x - 6 = 0

A = 1
B = 5
C = -6

Δ = b² - 4 • a • c

Δ = 5² - 4 • 1 • ( -6)

Δ = 25 + 24

Δ = 49

X = ( -b ± √ Δ) / 2 • a

X = ( -5 ± √ 49 ) 2 • 1

X = ( - 5 ± 7 ) 2

X1 = - 5 + 7 / 2 = 2 / 2 = 1

X2 = - 5 - 7 / 2 = - 12/ 2 = -6

S { 1, - 6 }