Question

alguém pode me ajudar ?

Answer 1

a)  A= 1     B = -7   C = 10

Δ = b² - 4.A.C

Δ = ( -7)² - 4.1.10

Δ= 49-40

Δ= 9

x'= $\frac{-(-7)+\sqrt{9} }{2.1}$ = $\frac{7+3}{2} = \frac{10}{2}  = 5$

x'' = $\frac{-(-7) - \sqrt{9} }{2.1} = \frac{7-3}{2} = \frac{4}{2} = 2$

b)  A= 1     B = -5   C = 6

Δ = b² - 4.A.C

Δ = ( -5)² - 4.1.6

Δ= 25-24

Δ= 1

x'= $\frac{-(-5)+\sqrt{1} }{2.1}$ = $\frac{5+1}{2} = \frac{6}{2}  = 3$

x'' = [$\frac{-(-5)-\sqrt{1} }{2.1}$ = $\frac{5-1}{2} = \frac{4}{2}  = 2$