Question

resolva o sistema a seguir: 2x+y=16 x2+xy+48

Answer 1

x^2-x (2x-16) = 48

x^2 – 2x^2 +16x = 48

x^2 - 16x + 48 = 0

delta = 16^2- 4•48 = 64

x = (16 ± 8 )/2 = 8 ± 4, x1= 12, x2=4

y1 = 2x1-16 =24-16 = 8

y2 = 2x2-16 = 8-16 = -8