Question

0,8³z-1,2 y³z + 0,3 y³z

Answer 1

0,8³z-1,2 y³z + 0,3 y³z=>


(4/5)^3 z - 6/5y^3 + 3/10y^3=>

z=( ( 4/5)^3 - 6/5y^3 + 3/10y^3 )=>

z. ( 64/125 - 9/10y^3 )=>

Z.1/250 . ( 128 - 225y^3)=>

1/250Z. ( 128 - 225y^3 )