Question

alguém me ajuda



4x⁴- 17x²+4=0

Answer 1

4x⁴- 17x²+4=0

x²= u

4u²-17u+4=0

a= 4 b=-17 c=4

Δ= b²-4ac

Δ= (-17)² -4·4·4

Δ= 289 - 64

Δ= 225

u= -b +/- √Δ

          2a

u= 17 +/-√225

          2·4

u= 17+/-15

        8

u'= 17+15 =  4

          8

u''= 17-15=  2 = 1

         8         8     4

S:[1/4 ,4]

u=x²

logo u= {1/4 ,4}

1/4= x²

x'= √1/4

x'= + 1/2 , -1/2

4=x²

x=√4

x= +2, -2

S:{ +1/2, -1/2,+2,-2}

Answer 2

4x⁴- 17x²+4=0

x²= u

4u²-17u+4=0

a= 4 b=-17 c=4

Δ= b²-4ac

Δ= (-17)² -4·4·4

Δ= 289 - 64

Δ= 225

u= -b +/- √Δ

          2a

u= 17 +/-√225

          2·4

u= 17+/-15

        8

u'= 17+15 =  4

          8

u''= 17-15=  2 = 1

         8         8     4

S:[1/4 ,4]

u=x²

logo u= {1/4 ,4}

1/4= x²

x'= √1/4

x'= + 1/2 , -1/2

4=x²

x=√4

x= +2, -2

S:{ +1/2, -1/2,+2,-2}