Respostas
respondido por:
2
3x^2-2x-1=0
delta=b^2-4ac
delta=(-2)^2-4.3. (-1)
delta=4+12
delta=16
x=-b-/+ raiz de delta/2a
x=-(-2)-4/2.3
x=2-4/6
x=-2/6 (:2)
x=-1/3
x=-(-2)+4/2.3
x=2+4/6
x=6/6
x=1
delta=b^2-4ac
delta=(-2)^2-4.3. (-1)
delta=4+12
delta=16
x=-b-/+ raiz de delta/2a
x=-(-2)-4/2.3
x=2-4/6
x=-2/6 (:2)
x=-1/3
x=-(-2)+4/2.3
x=2+4/6
x=6/6
x=1
respondido por:
0
3x-2x-1=0
Delta=b²-4ac
=(-2)²-4(3)(-1)
=4+12
=16
x'=(-b+√Delta)/2a
x'=(2+4)/2.3
x'=6/6
x'=1
x''=(-b-√Delta)/2a
x''=(2-4)/2.3
x''=-2/6 :2
x''=-1/3
Delta=b²-4ac
=(-2)²-4(3)(-1)
=4+12
=16
x'=(-b+√Delta)/2a
x'=(2+4)/2.3
x'=6/6
x'=1
x''=(-b-√Delta)/2a
x''=(2-4)/2.3
x''=-2/6 :2
x''=-1/3
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