Question

Alguém me ajuda a calcular não consigo por favor

Answer 1

a) ( $\sqrt{\sqrt{\sqrt{32} }$)³  =  ⁸√2¹⁵  ou  2¹⁵/⁸

b)  $(\frac{2\sqrt{16} } {2} )^\frac{1}{2} =(\frac{2.4}{2})^\frac{1}{2} = (\frac{8}{2} )^\frac{1}{2} =4^\frac{1}{2} = \sqrt{4} = 2$

c) $4^\frac{3}{2} (\frac{5}{4} )= \sqrt{4^3} (\frac{5}{4} )=\sqrt{64} (\frac{5}{4)} = 8(\frac{5}{4} )=\frac{40}{4} = 10$

d) $\frac{3^3}{27} - \frac{9}{3^2} +\frac{3^4}{81}= \frac{27}{27} -\frac{9}{9} +\frac{81}{81} = 1-1+1 = 1$

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Refazendo a letra "b" com a elevação da raiz de 16:

$(\frac{2^\sqrt{16} }{2} )^\frac{1}{2} =( \frac{2^4}{2} )^\frac{1}{2} =(2^3)^\frac{1}{2} = \sqrt{2^3} = \sqrt{8}  ~~~ou~~2^\frac{3}{2}$