Question

Calcule x na equação. 
a) (x+1)(2x-1)=0

Answer 1

$(x+1)(2x-1)=0$
$2x^{2}-x+2x-1$
$2x^{2}+x-1$
a=2 b=1 c=-1
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-1\pm\sqrt{(1)^2-4*2*(-1)}}{2*2}$

$x=\frac{-1\pm\sqrt{1-(-8)}}{4}$

$x=\frac{-1\pm\sqrt{9}}{4}$

$x=\frac{-1\pm3}{4}$
$x'= -1$
$x''= \frac{2}{4}$

ou simplificando
$x''= \frac{1}{2}$

Espero ter ajudado'

Answer 2

(x+1) (2x-1)=0

x+1=0

x=-1

2x-1=0

2x=1

x=1/2