• Matéria: Matemática
  • Autor: joananatielle
  • Perguntado 7 anos atrás

A) 72-5x(27:3-6) =


B) (20:5+3)x22 =

C) 33:{10+[6:3+(1+2)]-4} =

D) 120+{560:[40+(300:10)]-19 =

E) 360:{100-[50-(2x3+4)]}+40 =

Respostas

respondido por: dopplergamma
2

a) \\ 72 - 5 \times ( \frac{27}{3 - 6} ) \\ 72 - 5 \times  \frac{27}{ - 3}  \\ 72 + 5 \times 9 \\ 117
b) \\ ( \frac{20}{5 + 3} ) \times 22 \\  \frac{20}{8}  \times 22 \\  \frac{5}{2}  \times 22 \\ 5 \times 11 \\ 55
c) \\  \frac{33}{(10 + ( \frac{6}{3 + ( 1 + 2)}) - 4) }  \\  \frac{33}{(10 +  \frac{6}{6}  - 4)}  \\  \frac{33}{7}
d) \\ 120  +  \frac{560}{(40 + ( \frac{300}{10})) }  - 19 \\ 120 +  \frac{560}{40 + 30}  - 19 \\ 120 +  \frac{560}{70}  - 19 \\ 120 + 8 + 19 \\ 109
e) \\  \frac{360}{100 - (50 - (2 \times 3 + 4))}  + 40 \\  \frac{360}{100 - (50 - 10)}  + 40 \\  \frac{360}{60}  + 40 \\ 6 + 40 \\ 46

Perguntas similares