Question

10Y-5(1+Y)=3(2Y-2)-20

PFV É PRA AMANHA

Answer 1

10Y-5(1+Y)=3(2Y-2)-20
10Y-5-5Y=6Y-6-20
10Y-5Y-6Y=-20-6+5
-1Y=-21
Y= -21 / -1
Y= 21

Answer 2

10y-5(1+y)=3(2y-2)-20
10y-5-5y=6y-6-20
10y-5y-6y=-6-20+5
-y=-21(-1)
y=21