Question

Considere log 2 base base a=0,69 e log 3 base a=1,10
Calcular:
A: log 16
B: log 18
C: log 24

Answer 1

A) $log16=log2^4=4.log2=4*0,69=2,76$

B) $log18=log2.3^2=log2+log3^2=0,69+2.log3==>\\=0,69+2.1,10=2,89$

C) $log24=log8.3=log2^3+log3=3.log2+log3=3.0,69+1,10=3,17$