Question

Resolva a equação
2^x + 2^x-1=3
3^x + 3^x-1=4

Answer 1

$2^x + 2^x-1=3\\ \\2\cdot2^x=3+1\\ \\2^x=\frac{4}{2}\\ \\2^x=2^1\\ \\x=1$

$3^x + 3^x-1=4\\ \\2\cdot3^x=4+1\\ \\3^x=\frac{5}{2}\\ \\3^x=2,5$

Fazendo o logaritmo:

$\log_{2,5} 3 = 0,835$

Portanto:

$3^x=2,5\\ \\3^x=3^{0,835}\\ \\x=0,835$