Question

a) -2x2 – 6x = 0

b) -m2 + 16 = 0

c) a2 = 1

Answer 1

a)
$-2 x^{2} -6x=0 \\ -2x(x+3)=0 \\ x=0 \\ x=-3$

b)
$-m^2+16=0 \\ m^2=16 \\ \\ m_1=-4 \\ \\ m_2=4$

c)
$a^2=1 \\ \\ a_1=-1 \\ a_2=1$

Answer 2

a) -2x^2 - 6x = 0
- 2x(x + 3) = 0
- 2x = 0
x = 0/-2
x = 0

x + 3 = 0
x = - 3

b) - m^2 + 16 = 0
- m^2 = - 16 .(-1)
m^2 = 16
m = raiz 16
m = +_ 4

m= - 4 e m= 4

c) a^2 = 1
a = raiz 1
a = +_ 1

a= - 1 e a= 1

ESPERO TER AJUDADO!