Question

x ao quadrado - 8 m x + 15 m ao quadrado igual a zero

Answer 1

$x {}^{2} - 8mx + 15m {}^{2} = 0$
$64m {}^{2} - 4 \times 15m {}^{2} = \\ 4m {}^{2}$
delta =
$4m {}^{2}$
$(- ( - 8) + - \sqrt{4m {}^{2} } ) \times \frac{1}{2}$
(8 +- 2m) × 1/2

x1 = 4 + m
x2= 4 - m