Question

(30y6-48y5-18y2):(6y2)

Answer 1

$\frac{30y^6-48y^5-18y^2}{6y^2}\\\\\\\frac{\left(30y^6-48y^5-18y^2\right)\,.\,y^{-2}}{6}\\\\\\\frac{(30y^6\,.\,y^{-2})-(48y^5\,.\,y^{-2})-(18y^2\,.\,y^{-2})}{6}\\\\\\\frac{(30y^{6-2})-(48y^{5-2})-(18y^{2-2})}{6}\\\\\\\frac{30y^{4}-48y^{3}-18y^{0}}{6}\\\\\\5y^{4}-8y^{3}-3$