Question

$\frac{-2^{4}-3x(-16) }{(-2)^{2} }$ me ajudem por favor

Answer 1

$\frac{-2^{4}-3x(-16)}{(-2)^{2} } = \frac{-2^{4}-3x(-16)}{4} = \frac{-16-3x(-16)}{4} = \frac{-3x-32}{4} = (\frac{-3x-32}{4}) \times 4 = -3x-32$