Question

Calcule o valor de x nas figuras abaixo :

Answer 1

a)

(x+1)^2=(3)^2+(x)^2

x^2+2x+1= 9+x^2

x^2-x^2+2x+1-9=0

2x-8=0

2x= 0+8

2x= 8

x= 8/2

x= 4

b)

(x+2)^2= (x+1)^2+x^2

x^2+4x+4= x^2+2x+1+x^2

x^2-x^2-x^2+4x-2x+4-1=0

-x^2+2x+3=0

x^2-2x-3= 0

∆= b^2-4.a.c

∆= (-2)^2-4.(1).(-3)

∆= 4+12

∆= 16

x=-b+-√∆

___----------

_____2.a

x= -(-2)+√16

___--------------

_____2.(1)

x= +2+4

__----------

_____2

x= 6/2

x= 3

x= +2-4

___-------

_____2

x= -2/2

x= -1