Question

Como resolver passo a passo
(3x-1)^2+(x-2)^2=25

Answer 1

$(3x-1)^2+(x-2)^2=25\\9x^2-6x+1+x^2-4x+2=25\\10x^2-10x-22=0\\5x^2-5x-11=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(5)(-11)}}{2(5)}\\\\x=\dfrac{5\pm\sqrt{245}}{10}\\\\x=\dfrac{5\pm7\sqrt{5}}{10}$