Question

ajudaaa por favor!
CALCULE:

a) log 1000

b) log 0, 001

c) log 10000

d) log7 49

Answer 1

Resposta:

a) log 1000 =log 10³ =3 log 10 = 3*1=3

b) log 0, 001 =log 10^(-3)  =(-3) * log 10 =-3

c) log 10000 =log 10^4  = 4 * log 10 =4

d) log7 49 =log 49 /log 7 = log 7²/log 7 = 2 * log 7/log 7  =2

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log 10 = 1

log[a] b = log b/ log a   .........[a] é a base

log a^b = b * log a

log a^(-b)  = -b * log a