Question

a temperatura de 1220 f corresponde a

Answer 1

5.°F - 160 = 9.°C
5.1220 - 160 = 9.°C 
5940 = 9.°C
°C = 5940/9
°C = 660

°F - 32/9 = K - 273/5
1220 - 32/9 = K - 273/5
132 = K - 273/5
K - 273 = 132*5
K = 660 + 273
K = 933

1220°F = 660°C = 933 K