Question

resolva:
a)x2-13x+22 =0
b) x2 +2x -35=0

Answer 1

Resposta:

Explicação passo-a-passo:

x²-13x+22 =0

delta=b²-4ac

delta=(-13)²-4*1*22

delta=169-88 =>81

x=(-b±√Δ)/2a

x=(13±√81)2*1

x=(13±9)/2

x'=(13+9)/2 =>11

x''=(13-9)/2 =>2

x² +2x -35=0

delta=b²-4ac

delta=2²-4*1*(-35)

delta=4+140 =>144

x=(-b±√Δ)/2a

x=(-2±√144)2*1

x=(-2±12)/2

x'=(-2+12)/2 =>5

x''=(-2-12)/2 => -7