• Matéria: Matemática
  • Autor: anymayaranunez
  • Perguntado 7 anos atrás

(FUVEST) O VALOR DE (0,2) ³ + (0,16)²;

(A)0,0264
(b)0,0336
(C)0,1056
(D)0,2568
(E)0,6256

Respostas

respondido por: Marcelloka
65
(B) 0,0336
0,2x0,2x0,2=0,008
0,16x0,16=0,0256

anymayaranunez: obrigadinha
respondido por: Anônimo
8

\sf \left(0,\:2\right)^3+\left(0,\:16\right)^2\\\\\\0.2^3=0.008\\\\\\=0.008+0.16^2\\\\\\0.16^2=0.0256\\\\\\=0.008+0.0256\\\\\\\to \boxed{\sf =0.0336}

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