Question

(3X-1)²=1
me ajuda aí gente !!!!!!

Answer 1

$\large\boxed{\boxed{{Ol\'a\:Monike}}}}}$

Respondendo detalhamente!

$(3x-1)^2=1$

$(3x-1)(3x-1)=1$

$9x^2-3x-3x+2=1$

$9x^2-6x+2-1=0$

$9x^2-6x+1=0$

onde:

a = 9 ; b = -6 e c = 1

lembrando que:

$\Delta=b^2-4.a.c$

$\Delta=(-6)^2-4.9.1$

$\Delta=36-36$

$\Delta=0$

$x_{1},_{2}=\frac{-b±\sqrt{\Delta}}{2.a}$

$x_{1}=\frac{6+\sqrt{0}}{2.9}$

$x_{1}=\frac{6+0}{18}$

$x_{1}=\frac{6}{18}$

$x_{2}=\frac{6-\sqrt{0}}{2.9}$

$x_{2}=\frac{6-0}{18}$

$x_{2}=\frac{6}{18}$

$\underline{Espero\:ter\:Ajudado}$