Question

Oi me ajudem por favor equação de 2° grau (bhaskará)
9X²+30X+16=0

Answer 1

Olá,

Aplicando a fórmula de Bhaskára:

$9x^2+30x+16=0\\\\Coeficientes:\;a=9,\;b=30\;e\;c=16\\\\\Delta=b^2-4ac\\\Delta=30^2-4\cdot9\cdot16\\\Delta=900-576\\\Delta=324\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{-30\pm\sqrt{324}}{2\cdot9}\\\\x=\dfrac{-30\pm18}{18}\\\\x_1=\dfrac{-30-18}{18}=\dfrac{-48}{18}=\boxed{-\dfrac{8}{3}}\\\\x_2=\dfrac{-30+18}{18}=\dfrac{-12}{18}=\boxed{-\dfrac{2}{3}}$

Espero ter ajudado.

Bons estudos! :)

Answer 2

Explicação passo-a-passo:

9X²+30X+16=0

a=9

b=30

c=16

∆=b²-4.a.c

∆=(30)²-4.(9).(16)

∆=900-576

∆=324

x'=[-(30)+√324]/2.(9)

x'=[-30+18]/18

x'=12/18

x'=12÷6/18÷6

x'=2/3

x"=[-(30)-√324]/2.(9)

x"=[-30-18]/18

x"=[-48]/18

x"=-48/18

x"=-48÷6/18÷6

x"=-8/3

Espero ter ajudado!