Question

Oi alguém consegue resolver?


35=[x.(x-3)]/2

Answer 1

35=[x.(x-3)]/2

35.2= x . x - x . 3

70= x^2-3x

x^2-3x-70=0

a= 1

b= -3

c= -70

Δ= b^2 - 4.ac

Δ= 9 - (-280)

Δ= 9 + 280

Δ= 289

X1= -(-3)+√289/2.1=10

X1= 3+17/2=10

X2= -(-3)-√289/2.1=10

X2= 3-17/2=10= -7

Resposta: 10, -7